Z-Score Calculator
Calculate a Z-score, percentile, and probability for one value or standardize every value in a dataset.
Z-Score
1.000
(85 - 75) / 10
Percentile
84.1%
Better than 84.1% of values
P(X ≤ 85)
84.13%
Area to the left
P(X > 85)
15.87%
Area to the right
Standard Ranges
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What is Z-Score Calculator?
A Z-score (also called a standard score) tells you how many standard deviations a value is from the mean. It standardizes values from any normal distribution, allowing you to compare values from different datasets and determine how typical or unusual a value is.
Z-Score Formula
- Z = (X - μ) / σ
- Z: Z-score (standard score)
- X: The value you're analyzing
- μ: Population mean
- σ: Population standard deviation
Interpreting Z-Scores
- Z = 0: Value equals the mean
- Z > 0: Value is above the mean
- Z < 0: Value is below the mean
- |Z| < 1: Typical (within 1 standard deviation)
- |Z| ≥ 2: Unusual (rare occurrence)
- |Z| ≥ 3: Extremely rare (outlier)
Practical Applications
- Education: Compare test scores across different exams or classes
- Psychology: Interpret IQ scores, personality assessments
- Medicine: Evaluate lab results, growth charts, vital signs
- Business: Analyze sales performance, quality control, market research
- Sports: Compare athlete performance across different metrics
- Quality Control: Identify defective products or processes
Z-Score and Percentiles
- Z-scores can be converted to percentiles using the standard normal distribution
- A Z-score of 0 corresponds to the 50th percentile
- A Z-score of 1 corresponds to approximately the 84th percentile
- A Z-score of -1 corresponds to approximately the 16th percentile
Assumptions and Limitations
- Most useful when data follows a normal (bell-shaped) distribution
- Requires knowing or estimating the population mean and standard deviation
- Less meaningful for severely skewed or non-continuous data
- Outliers can significantly affect the mean and standard deviation
Worked Z-Score Example
A test score of 85 from a distribution with mean 75 and standard deviation 5 has:
Z = (85 - 75) / 5 = 2
The score is two standard deviations above the mean. Under a normal-distribution interpretation, that is approximately the 97.7th percentile.
Method reference: NIST Engineering Statistics Handbook: Z-scores and outlier detection.
